There is one way to roll a sum of 12. There are 36 different outcomes from rolling a pair of dice. Therefore, the probability is 1/36 ~= 0.0278 = 2.78%
If the question is: What are the odds of rolling a die with a 6 when rolling twodice ? . Answer: There are 36 outcomes when rolling a pair of dice, 10 of themhave a die with a single 6 and 1 of them has two 6. So the probability of rollingone die with a 6 when rolling a pair of dice is P =10/36 =0.2777... . The oddswould be (10 to 26) 5 to 13.If the question is: What are the odds of rolling a sum of 6 when rolling two dice ?Answer: there are 5 outcomes out of the 36 that give the sum of 6. They are;(1,5), (5,1), (2,4), (4,2), and (3,3). So the probability for this event is P =5/36 =0.13888... . The odds would be 5 to 31.
3 times (out of 36) is the probablility Possible Outcome 1 - Dice 1: 4, Dice 2: 6 Possible Outcome 2 - Dice 1: 5, Dice 2: 5 Possible Outcome 3 - Dice 1: 6, Dice 2: 4
In rolling two fair dice, the probability of obtaining a sum greater than 10 is 3 in 36 or 1 in 12, and the probability of obtaining a sum divisible by 6 is 6 in 36 or 1 in 6. Since the two probabilities come from the same population of 36 possible outcomes, the combined probability is the inclusive or of the two result sets, 8 in 36 or 2 in 9. The results that match the sum>10 target are 5-6, 6-5, and 6-6. The results that match the divisibility by 6 target are 1-5, 2-4, 3-3, 4-2, 5-1, and 6-6. The results that match the combined target are 1-5, 2-4, 3-3, 4-2, 5-1, 5-6, 6-5, and 6-6.
Of all the six numbers on a cube, only the '5' is not a factor of 12.Probability of rolling a factor of 12 on the first cube = 5/6 .Probability of rolling a factor of 12 on the second cube = 5/6 .Probability of rolling a factor of 12 on both cubes = (5/6 x 5/6 ) = 25/36 = 694/9 %.
It is 0.0833... recurring.
There is one way to roll a sum of 12. There are 36 different outcomes from rolling a pair of dice. Therefore, the probability is 1/36 ~= 0.0278 = 2.78%
It is 10/36 = 5/18 in a single throw of a pair of dice.
8/36=4/18=2/9=22.22%
With 3 fair dice, pipped 1 through 6, there are 10 permutations that add up to 6. They are 114, 123, 132, 142, 213, 222, 231, 312, 321, and 411. The total number of permutations of the three dice is 63 or 216. The probability, then, of rolling a sum of 6 on 3 dice is 10 in 216, or 5 in 108, or about 0.0463.
Assuming that the random variable is the sum of the two numbers rolled, the answer is 3/36 or 1/12.
If the question is: What are the odds of rolling a die with a 6 when rolling twodice ? . Answer: There are 36 outcomes when rolling a pair of dice, 10 of themhave a die with a single 6 and 1 of them has two 6. So the probability of rollingone die with a 6 when rolling a pair of dice is P =10/36 =0.2777... . The oddswould be (10 to 26) 5 to 13.If the question is: What are the odds of rolling a sum of 6 when rolling two dice ?Answer: there are 5 outcomes out of the 36 that give the sum of 6. They are;(1,5), (5,1), (2,4), (4,2), and (3,3). So the probability for this event is P =5/36 =0.13888... . The odds would be 5 to 31.
There are 36 permutations of two dice. Of these, 10 sum to less than six; 1+1, 1+2, 1+3, 1+4, 2+1, 2+2, 2+3, 3+1, 3+2, and 4+1. The probability, then, of rolling a sum less than six is 10 in 36, or 5 in 18, or about 0.2778.
It is 1/12.
The probability of rolling 6 ones with 10 dice is: 10C6 (1/6)6 (5/6)4 = 2.170635034...x 10-3 ≈ 0.22%
3 times (out of 36) is the probablility Possible Outcome 1 - Dice 1: 4, Dice 2: 6 Possible Outcome 2 - Dice 1: 5, Dice 2: 5 Possible Outcome 3 - Dice 1: 6, Dice 2: 4
The probability is 21/36 = 7/12