Well there is 36 different possibilities with rolling 2 6 sided dice.
The probability of rolling the sum of 10 with 2 die is 4/36 or 1/8 chance.
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There is one way to roll a sum of 12. There are 36 different outcomes from rolling a pair of dice. Therefore, the probability is 1/36 ~= 0.0278 = 2.78%
If the question is: What are the odds of rolling a die with a 6 when rolling twodice ? . Answer: There are 36 outcomes when rolling a pair of dice, 10 of themhave a die with a single 6 and 1 of them has two 6. So the probability of rollingone die with a 6 when rolling a pair of dice is P =10/36 =0.2777... . The oddswould be (10 to 26) 5 to 13.If the question is: What are the odds of rolling a sum of 6 when rolling two dice ?Answer: there are 5 outcomes out of the 36 that give the sum of 6. They are;(1,5), (5,1), (2,4), (4,2), and (3,3). So the probability for this event is P =5/36 =0.13888... . The odds would be 5 to 31.
3 times (out of 36) is the probablility Possible Outcome 1 - Dice 1: 4, Dice 2: 6 Possible Outcome 2 - Dice 1: 5, Dice 2: 5 Possible Outcome 3 - Dice 1: 6, Dice 2: 4
In rolling two fair dice, the probability of obtaining a sum greater than 10 is 3 in 36 or 1 in 12, and the probability of obtaining a sum divisible by 6 is 6 in 36 or 1 in 6. Since the two probabilities come from the same population of 36 possible outcomes, the combined probability is the inclusive or of the two result sets, 8 in 36 or 2 in 9. The results that match the sum>10 target are 5-6, 6-5, and 6-6. The results that match the divisibility by 6 target are 1-5, 2-4, 3-3, 4-2, 5-1, and 6-6. The results that match the combined target are 1-5, 2-4, 3-3, 4-2, 5-1, 5-6, 6-5, and 6-6.
Of all the six numbers on a cube, only the '5' is not a factor of 12.Probability of rolling a factor of 12 on the first cube = 5/6 .Probability of rolling a factor of 12 on the second cube = 5/6 .Probability of rolling a factor of 12 on both cubes = (5/6 x 5/6 ) = 25/36 = 694/9 %.