The product of 13 x 3 is 39
1x52, 2x26, 3x13
3x13=39
To find the HCF of two numbers you first have to express them as a product of their prime factors. In this case: 15 = 3x5 39 = 3x13 The next step is to identify any common prime factors. In this case, both numbers have 3 as a prime factor. Therefore the HCF of 15 and 39 is 3.
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78 6 x 13 (2x3) x 13 The numbers 2, 3, and 13 are prime numbers, so the factor tree is complete. An alternate version of a factor tree for 78 is: 78 2 x 39 2 x (3x13)
3 x 13 = 39
1x52, 2x26, 3x13
3x13 39x1
3x13=39
3x13=39
I'm sure it's composite, 3x13=39
3 is a prime number. 13 is a prime number. 3 x 13 cannot be prime.
33 (3x11) 39 (3x13) 51 (3x17)
To find the HCF of two numbers you first have to express them as a product of their prime factors. In this case: 15 = 3x5 39 = 3x13 The next step is to identify any common prime factors. In this case, both numbers have 3 as a prime factor. Therefore the HCF of 15 and 39 is 3.
3 because they are all in multiples of 3 3x4 and 3x13
4x10 is 40 which is as close as you can get.If you want to get close but not 40 itself, then 3x13=39 which is closer then 4x9=36
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