I don't quite understand the phrasing of the question. In mathematics a product is the result of multiplication. If you have three numbers A, B and C Then A x B might be one product A x C might be the second product B x C might be the third product This would leave A x B x C as the fourth product. So, if we have 3, 5 and 7 then 3 x 5 = 15 3 x 7 = 21 5 x 7 = 35 and 3 x 5 x 7 = 105
2c + 3
Product
( A/B ) x ( C/D ) = ( A x C )/( B x D ) -- The numerator of the product is the product of the numerators. -- The denominator of the product is the product of the denominators.
"Product" is a binary operation. You cannot have a product of 3: it has to be the product of 3 and another number.
-3
//sum and product of 3 nos #include #include void main() { int a,b,c; printf("enter the 3 nos"); scanf("%d%d%d",&a,&b,&c); printf("sum of 3 nos",a+b+c); printf("product of 3 nos",a*b*c); getch(); }
I don't quite understand the phrasing of the question. In mathematics a product is the result of multiplication. If you have three numbers A, B and C Then A x B might be one product A x C might be the second product B x C might be the third product This would leave A x B x C as the fourth product. So, if we have 3, 5 and 7 then 3 x 5 = 15 3 x 7 = 21 5 x 7 = 35 and 3 x 5 x 7 = 105
3c+5
2c + 3
Product
Um, x2+3x-5=0? This is ax2+bx+c where a=1, b=3, and c=-5. The sum of the roots is -b/a so that means the sum of the roots is -3. Also, product of the roots is c/a. That means the product of the roots is -5. -3+(-5)= -8. There you have it.
As a product of its prime factors: 3*3*3*3 = 81 and 4*3 = 12
the product between A and a substraction of B and C is the same than the the product of A and B, minus the product of A and C A x (B-C) = (A x B)-(A x C) 8 x (5-3) = (8x5)-(8x3) 8x2 = 40-24 16 = 16
24bc = 2*2*2*3*b*c
The numerator of the product is the product of the three numerators and the denominator of the product is the product of the three denominators.So, for example, (a/b)*(c/d)*(e/f) = (a*c*e)/(b*d*f)
If a is to b as c is to d, a x d = b x c. The product of the means (b & c) equals the product of the extremes (a & d).