Yes. It does not have to be an exact value.
By adding simple logic you can round off to single digit. In any value you add 0.05 and pick only one digit after the decimal and the result will be the value after rounding off in one decimal place.
To round off 63214 to the highest place value, we look at the digit in the ten thousands place, which is 6. The next highest place value is the hundred thousands place. Since the digit in the ten thousands place is 5 or greater, we round up to the next hundred thousands, making it 70000.
The number that lies halfway between 8500 and 10000 can be calculated by finding the average of the two numbers. Add 8500 and 10000 together to get 18500, then divide by 2 to find the average, which is 9250. Therefore, 9250 is the number that lies halfway between 8500 and 10000.
Round off to the nearest cent, means round off to the nearest hundredths or round off to two decimal.
The digit in the hundreds place is 2, and the digit on the tens place is 5, which is on right of 2. Since 5 is at least 5, we round up the value to get 9300.
I would suggest 9200 * 30 = 9000*30 + 200*30 = 270000 + 6000 = 276000.
£9250 is $11,225
9250 is between zero and ten thousand. It is closer to ten thousand than it is to zero. 9250 to the nearest thousand is 9000. 9250 to the nearest ten thousand is 10000.
9250 meters are 9.25 kilometers.
To round off to the nearest integer... double a = {some value}; a = (int) (a + 0.5); To round off to the nearest hundredth... double a = {some value}; a = (int) (a * 100. + 0.5) / 100.; These are just two examples.
Rounded value is 5.
Yes. It does not have to be an exact value.
ahm
No because it is an absolute value
Name the place value, and we'll zero in on it.
By adding simple logic you can round off to single digit. In any value you add 0.05 and pick only one digit after the decimal and the result will be the value after rounding off in one decimal place.