The nth term is 4n - 3
The special divisibility rule of 17 is "Take the difference of the rest of the digits and the last digit times 5." For instance: 17 1 - 7 * 5 = 1 - 35 = -34 which is divisible by 17.
There are 10 possible combinations so 60 possible permutations. The combinations are:(1, 3, 21), (1, 5, 19), (1, 7, 17), (1, 9, 15), (1, 11, 13),(3, 5, 17), (3, 7, 15), (3, 9, 13), (5, 7, 13), (5, 9, 11).
1 5 9 13 17 21
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The nth term is 4n - 3
The rule is t(n) = 5 + 2*n, where n = 1, 2, 3, ...
The special divisibility rule of 17 is "Take the difference of the rest of the digits and the last digit times 5." For instance: 17 1 - 7 * 5 = 1 - 35 = -34 which is divisible by 17.
1, 3, 5, 7, 9, 11, 13, 15, 17, 19. 1, 3, 5, 7, 9, 11, 13, 15, 17, 19. 1, 3, 5, 7, 9, 11, 13, 15, 17, 19. 1, 3, 5, 7, 9, 11, 13, 15, 17, 19.
There are infinitely many possible answers. The simplest, linear, rule is Un = 4n - 17 for n = 1, 2, 3, ...
5, 13 and 17 are prime.
There are 10 possible combinations so 60 possible permutations. The combinations are:(1, 3, 21), (1, 5, 19), (1, 7, 17), (1, 9, 15), (1, 11, 13),(3, 5, 17), (3, 7, 15), (3, 9, 13), (5, 7, 13), (5, 9, 11).
1 5 9 13 17 21
t(n) = 5 + 2*n
2+3+5+7=17 or 1 and 7 or 1 + 3 + 13=17 or 5 + 5 +5 + 2 =17 or 3 + 7 + 7=17.
The prime numbers from 1 to 17 are 2, 3, 5, 7, 11, 13, and 17.
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