multiply each number by 2
Double the previous number.
What is the value of the 8th term of the sequence 4, 8, 16, 32,?what is the answers?1,024,512,128or2,048.
gcf(16, 32, 48) = 16. 16 = 2^4 32 = 2^5 48 = 2^4 x 3 hcf = 2^4 = 16
The factors of 32 are 1, 2, 4, 8, 16, and 32. The factor pairs of 32 are 1 x 32, 2 x 16, and 4 x 8. 2* 16= 32 32* 1= 32 4* 8= 32
1 × 64 = 64 2 × 32 = 64 4 × 16 = 64 8 × 8 = 64 16 × 4 = 64 32 × 2 = 64 1 × 32 = 32 2 × 16 = 32 4 × 8 = 32 8 × 4 = 32 16 × 2 = 32 32 × 1 = 32
Double the previous number. tn = 2n
1, 2, 4 1, 2, 4, 8, 16 1, 2, 4, 8, 16, 32
1, -1, 2, -2, 4, -4, 8, -8, 16, -16, 32, -32
1, -1, 2, -2, 4, -4, 8, -8, 16, -16, 32, -32
1, -1, 2, -2, 4, -4, 8, -8, 16, -16, 32, -32
1, -1, 2, -2, 4, -4, 8, -8, 16, -16, 32, -32