Multiply each preceding term by 4.
It is increasing by odd numbers consecutively._______or: n = the term number, the rule is: n2 or n(n). 12=1(1x1=1), 22=4(2x2=4), 32=9(3x3=9), and so on.
The rule is 5, 10, 15 and so the next number will be 20+31 = 51
There are actually more than a pattern rule for that type of sequence. The pattern rule is not obvious. The sequence is actually this: an = 5a(n - 2) for n > 2, such that the seed values are a1 = 1 and a2 = 5. Another pattern rule is the number of palindromes using a maximum of five different symbols. The third one is the Inverse Binomial Mean transformation of the Fibonacci sequence.
So you're adding 3, 5, 7, 9, 11 etc 1, 4, 9, 16, 25, 36, 49
Double the previous number
t(n) = n2
add 3,5,7,9and then to 25 add 11, adding odd numbers onto the last . 1+3=4, 4+5=9, 9+7=16, 16+9=25, 25+11=36 and so on
Yes.
Yes
Multiply each preceding term by 4.
It is increasing by odd numbers consecutively._______or: n = the term number, the rule is: n2 or n(n). 12=1(1x1=1), 22=4(2x2=4), 32=9(3x3=9), and so on.
t(n) = (n+1)2 where n = 1, 2, 3, ...
The rule is 5, 10, 15 and so the next number will be 20+31 = 51
assuming you mis-typed the 15 and instead it should be a 25, these are simply the squares of the number's position in the line. 12 = 1 22 = 2 32 = 9 42 = 16 52 = 25 (assume is what you meant) 62 = 36 You can also think of it as adding on the next in a series of odd numbers 1+3 = 4 4+5 = 9 9+7 = 16 which results from expanding (x+1)2 - x2 anyway
no it is not a recursive pattern because it isn't equal numbers.
from 12 to 16 is 4 then from 16 to fiftine is one then from15-19 is 4 so one so forth one is +4 the next is -1