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1 2 5 14 41

Since every term is expressed with respect to the immediately preceding term, this is a recursive sequence, where t1 = 1 and tn+1 = 3tn - 1, n = 1, 2, 3, ...

t1 = 1
t2 = 3(1) - 1 = 2
t3 = 3(2) - 1 = 5
t4 = 3(5) - 1 = 14
t5 = 3(15) - 1 = 41
next
t6 = 3(41) - 1 = 122

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What is the missing number in sequence 2 - 5 - 14 - - 122?

The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.


What number is missing out of 2- 5- 14-122?

Type your answer here... The sequence has the formula is 3x - 1 2 → 6 - 1 = 5 5 →15 - 1 = 14 14 →42 -1 = 41 41 → 123 - 1 = 122 The missing number is therefore 41.


Find the next three numbers to the sequence of 1 2 5 14?

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The sequence 2, 5, 14, 41, 122 appears to follow a pattern where each term is generated by multiplying the previous term by 3 and then adding 1, starting with 2. Specifically, the calculations are as follows: (2 \times 3 + 1 = 5), (5 \times 3 - 1 = 14), (14 \times 3 - 1 = 41), and (41 \times 3 - 1 = 122). This rule can be expressed as (a_n = 3a_{n-1} - 1) for (n > 1).


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