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Each exterior angle is 360/6 = 60 degrees

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โˆ™ 6y ago
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โˆ™ 3y ago

60 degrees ok

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Q: What is the size of one exterior angle in a regular hexagon?
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What are the size of exterior angles of hexagon?

Providing that it is a regular 6 sided hexagon then each exterior angle measures 60 degrees


Calculate the size of the exterior angle of a regular hexagon?

interior = 720/6 = 120 so exterior = 180 - 120 = 60 degrees


What is the interior and exterior angle of a regular hexagon?

Imagine the angle you want to find is part of a circle - 360 degrees. Since a hexagon has 6 sides, you have to divide 360 by 6. This gives you 60. 60 degrees is the size of the exterior angle. You should know that a straight line is 180 degrees. So all you have to do is take away 60 from 180, giving you an answer of 120 degrees. This is the size of your interior angle.


How do you determine the size of the angles of a regular hexagon?

The sum of exterior angles of any polygon= 360degreeA hexagon has 6 sides, hence 6 vertices. At each vertex there is a linear pair of one exterior angle and one interior angle. So, we get 6 exerior angles.Therefore, each exterior angle = 360 degree/6= 60 degree.Hence, each interior angle= (180 - 60) degree= 120 degree.


What is the size of one interior angle in a regular octagon?

135 degrees and its exterior angle is 45 degrees


A regular polygon an exterior angle of 30 What is the size of the interior angle?

Exterior angles are supplementary with interior angles, so 180-30=150


What is the size of each angle in a regular 25 sided shape?

Exterior angle = 14.4 degrees Interior angle = 165.6 degrees


What is the size of an interior angle of a 20 sided regular polygon?

exterior angle = 360° ÷ 20 sides = 18° interior angle = 180° - exterior angle = 180° - 18° = 162°


What is the size of each interior angle of a regular polygon with 28 sides?

The easiest way to calculate this is to calculate the exterior angle and use the fact that the exterior and interior angles are supplementary. Sum exterior angles = 360° → Each exterior angle of a regular 28-agon is 360° ÷ 28 → Each interior angle of a regular 28-agon = 180° - 360° ÷ 28 = 167 1/7° ≈ 167.14°


D Find the size of each exterior angle of a regular 20-gon?

162 degrees


What is the size of each exterior angle of a regular pentagon?

Interior angles are 108o. 360 - 108 = 252o for each exterior angle * * * * * Each exterior angle is 360/5 = 72 degrees, NOT 252. The 108 for the interior angle is correct, but to get from interior to exterior you subtract from 180, not 360!


How do you find out the size of a regular polygon?

Divide the number of sides into 360 which will give you the exterior angle and subtract this angle from 180 which will give you the interior angle.