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Since the line that passes through (-2, 5) it is parallel to the line with equation y = -x -1 and slope -1, then its slope is also -1, as parallel lines have the same slope.

In order to write the point-slope form of that line, we use the slope m = -1 and the point (x1, y1) = (-2, 5), such as

(y - y1) = m(x - x1)
y - 5 = -1(x - -2)
y - 5 = -1(x + 2)
y - 5 = -x - 2 (solve for y to obtain the slope-intercept form of the equation of the line)
y - 5 + 5 = -x + 5 - 2 (add 5 to both sides)
y = -x + 3

Thus, the slope-intercept form of the line that passes through (-2, 5) and parallel to the line with equation y = -x -1, is y = -x + 3.

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Q: What is the slope-intercept form of the equation through negative 2 5 parallel to y equals a negative x subtract 1?
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