Since the line that passes through (-2, 5) it is parallel to the line with equation y = -x -1 and slope -1, then its slope is also -1, as parallel lines have the same slope.
In order to write the point-slope form of that line, we use the slope m = -1 and the point (x1, y1) = (-2, 5), such as
(y - y1) = m(x - x1)
y - 5 = -1(x - -2)
y - 5 = -1(x + 2)
y - 5 = -x - 2 (solve for y to obtain the slope-intercept form of the equation of the line)
y - 5 + 5 = -x + 5 - 2 (add 5 to both sides)
y = -x + 3
Thus, the slope-intercept form of the line that passes through (-2, 5) and parallel to the line with equation y = -x -1, is y = -x + 3.
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the first step in solving the equation is to subtract the nine from the three. you will get negative 6.
If two negaitve signs occur next to each other in an equation, as in 4 -(-2) then the two negatives becomes a positive and you add the two to get 6. Otherwise, you just do what the equation states: -5 + 3 you add; =-2. -5 - 3 you subtract; = -8
No, you need to find out the numbers to subtract then subtract.
You will get a positive integer. If you subtract a negative number, you will be adding it. I think of it like 2 minuses equals a plus. :P
subtract