The slope is -4
5 and the y intercept is 2
The graph of [ y = 7 ] is a straight horizontal line, passing through the point [ y = 7 ]on the y-axis. The slope of a horizontal line is zero.
9
5
y - 3x = 8 standard form is y = mx + b m = slope y = 3x + 8 in this form slope m is 3 The perpendicular line slope is the negative inverse of m -1/m = -1/3
The slope is -0.2
5
There is no "equals" sign therefore "x-9" is NOT an equation.
x = -3 represents a vertical line whose slope is undefined.
-1/5
q2
-4
5 and the y intercept is 2
The equation has no slope. The graph of the equation is a straight line with a slope of -1 .
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
The equation, y = -4x - 3, is written in what's called slope-intercept form. The general equation for slope-intercept form is y = mx + b, where m is the slope of the line, and b is the y-intercept. So, for the equation in question, m = -4 and b = -3. Thus, the slope of the line is -4.
There is a standard equation for a straight line. It is y = mx + b. m is the slope and b is the y-intercept (when x = 0). In the question m = -4 and is therefore the slope of the line represented by the equation y = -4x + 7.