m(slope = Y2 - Y1/X2 - X1
(0, 4) and (4, - 2)
m = - 2 - 4/4 - 0
= - 6/4
= - 3/2
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The slope of the line joining the two pints is (4 - 2)/(-3 - 0) = -2/3 Therefore the slope of the perpendicular is 3/2
The slope is zero.
Points: (-6, 0) and (2, 4) Slope: (0-4)/(-6-2) = 1/2
No. A horizontal line has a slope of 0. A vertical line has an undefined slope. Let's say you have a vertical line with the points (3,-2) and (3,4). The slope is (y1-y2)/(x1-x2) = (-2-4)/(3-3) = -6/0 = undefined. Notice that x is the same for both points. A line in which all points have the same value for x is a vertical line and as such has an undefined slope.
A pair of points doesn't have a slope. But the line between them does.The line between (0, 3) and (8, -4) has a slope of -7/8 = -0.875 .
Points: (-2, 1) and (0, -3) Slope: -2
Points: (0, 7) and (8, -3) Slope: -5/4
If the points are: (0, 3) and (8, -3) then the slope works out as -3/4
It is: 0
Points: (8, 3) and (8, 7) Slope: 0 It will be a straight vertical line parallel to the y axis
Points: (8, -6) and (8, 2) Slope: 0 It is a straight line parallel to the y axis.
-3/2
Slope: (2-4)/(0--3) = -2/3 Perpendicular slope: 3/2
Slope = 7--3 over 0-8 = -5/4
6
If you mean points of: (0, 4) and (4, -2) then the slope works out as -3/2
Points: (-3, 6) and (4, 6) Slope: 0 The line will be a straight horizontal line parallel to the x axis