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Q: What is the slope of the line that is perpendicular to the line whose equation is 3x plus y equals 4?

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-5

4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3

The slope would be 3/4

ax + by = cThe graph if that equation is a straight line whose slope is (-a/b)and whose y-intercept is (c/b).

End points: (-2, 4) and (-4, 8) Midpoint: (-3, 6) Slope: -2 Perpendicular slope: 1/2 Perpendicular bisector equation: y -6 = 1/2(x--3) => y = 0.5x+7.5

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12

-5

It is: -1/2

the slope will be positive 1.5x the whole equation is y=4.5+1.5x

For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )

- 1/3

It is -1/2

4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3

If you mean y = 2x+5 then the perpendicular slope is -1/2

Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.

y = 0That's the equation of the x-axis.Its slope is zero.

x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.

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