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12. Call the smaller of the two consecutive even integers x and the larger y, and represent their relationship as x + 2 = y. The smaller of the two integers is 5 more than half the greater, which you can represent as x = y/2 + 5. Solving these two equations together gives you an x of 12 and a y of 14. Testing, we confirm that 12 is 5 more than half of 14, or 7.

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Q: What is the smaller of two consecutive even integers such that it is 5 more than one half of the greater?
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