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What is the smallest number divisible by 2 3 4 5 6 7 9 10 11 12 and 15?
Wiki User
∙ 13y ago
To find the least common multiple of all these numbers, you have to find a number that has all the prime factors of all these divisors.
So, the number has to be divisible by 2 2's, 2 3's, 1 5, 1 7, and 1 11. A 6 consists of one 2 and one 3. A 4 consists of 2 twos. A 9 consists of two 3's. A ten is one 2 and one 5. A 12 is two 2's and one 3. And 15 is one three and one five.
So, the number is 2*2*3*3*5*7*11 = 13860
Wiki User
∙ 13y ago
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