x = 3 and 1/3
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3x + 6 = 12Subtract 6 from each side:3x = 6Divide each side by 3:x = 2
If: 3x+2y = 5x+2y = 14 Then: 3x+2y = 14 and 5x+2y =14 Subtract the 1st equation from the 2nd equation: 2x = 0 Therefore by substitution the solutions are: x = 0 and y = 7
3x + 8 = 23 Subtract 8 from both sides: 3x = 15 Divide both sides by 3: x = 5
3x-3x equal = 0
y=(-1) x=(2)