If the question gives 4x-3=9, then we can solve:
4x-3=9
4x=6
x=3/2, or 1.5
The solution of 4x plus 3y -9 and x -3 is; 5x+3y-3.
5x - 9 = 4x 5x - 4x - 9 = 4x - 4x x - 9 = 0 x - 9 + 9 = 0 + 9 x = 9
4x + 3y=9 x=0 y=3
It is possible to factorise 4x²-9 further.Factorising is to express a number or expression as a product of factors.The technique of factorising two terms: a² - b² = (a + b) (a - b)If we apply ( 4x²-9 ) to the previous technique: 4x² - 9 = (2x + 3) (2x - 3)
8x^3 - 12x^2 + 6x - 9 = (8x^3 - 12x^2) + (6x - 9) = 4x^2(2x - 3) + 3(2x - 3) = (4x^2 + 3)(2x - 3)
-5x + x + 9 = -4x + 12 -4x + 9 = -4x + 12 9 = 12 This equation has no solution.
The solution of 4x plus 3y -9 and x -3 is; 5x+3y-3.
If you mean: 4x+3 = 6x-9 then the value of x works out as 6
5x - 9 = 4x 5x - 4x - 9 = 4x - 4x x - 9 = 0 x - 9 + 9 = 0 + 9 x = 9
(2x - 3)(4x + 9)(2x + 3) = (2x - 3)(2x + 3)(4x + 9) = [(2x)^2 - (3^2)](4x + 9) = (4x^2 - 9)(4x + 9) = (4x^2)(4x) + (4x^2)(9) - (9)(4x) - (9)(9) = 16x^3 + 36 x^2 - 36x - 81
4x+9=25 4x=16 x=4
3+6x = 4x+9 6x-4x = 9-3 2x = 6 x = 3
2(4x^3 - 9)(4x^3 + 9)
(4x-3)(4x+3)
The given expression can be simplified to: 4x -16
There are two simultaneous equations, so to solve for y, eliminate x: 1) 2x + 3y = 3 2) 4x - 3y = 9 Multiply equation (1) by 2 giving: 1) 4x + 6y = 6 2) 4x - 3y = 9 Next, subtract equation (2) from equation (1), giving: (4x - 4x) + (6y - -3y) = 6 - 9 → 9y = -3 → y = -1/3
4x+9 = 7x+3 4x-7x = 3-9 -3x = -6 x = 2