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I'm guessing you mean 20 ft. circumference?
With a 20' circumference, here's the math.
C=20; C(r)=2*[pi]*r; 2*[pi]*r=20; r=10/[pi]
A(r)=r2*[pi]; A=(10/[pi])2*[pi]; A= about 31.831 sq. ft.
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