That's the same as the square root of +112, times i.
Yes.
The square root of 121 is the number which multiplied by itself will give 121, the answer is 11. (11*11=121). we write 11*11 as 112 thus if 112 = 121, then the square root of 121 or √121= 11 as you can see a square root of a number is the opposite of the square of a number
The square root of 112 simplified is √112 = 4√7. Here's how you can break it down: First, find the prime factorization of 112: 112 = 2^4 * 7. Take the square root of each of the factors: √(2^4 * 7) = √(2^4) * √7 = 2^2 * √7 = 4√7. So, the simplified radical form of √112 is 4√7.
896 over 1000 in simplest form = 112/125
sqrt(112) = sqrt(16 x 7) = sqrt(16) x sqrt(7) = 4 sqrt(7)
That's the same as the square root of +112, times i.
(√112)/(√7) = √(112/7) = √16 = 4.
75/112 is already in simplest form.
112/C is in its simplest form.
112/297 is the simplest form.
112/132 = 28/33 in its simplest form
4 times the square root of 7
4 times the square root of 7.
If you factorise 112 then the expression can be re-written as :- √112 = √(16 x 7) ......as 16 = 42, this becomes :- √112 = 4√7...............if an answer in radical form is not acceptable then :- √112 = 10.583 (5sf)
Yes.
Yes, it is.