sqrt(2 + 121) = sqrt(123) = 11.09, approx.
11 units. (It is the square root of 121, and A=S^2 => 121=S^2 => S=11.)
The square root of 121 is the number which multiplied by itself will give 121, the answer is 11. (11*11=121). we write 11*11 as 112 thus if 112 = 121, then the square root of 121 or √121= 11 as you can see a square root of a number is the opposite of the square of a number
1 square root of 144 =12 square root of 121=11so 12-11=1
Yes, the square root of 121 is 11
(10)2 = 100 (11)2 = 121 Since 114 is between 100 and 121, its square root must be between 10 and 11.
Find the factors of 484484= (4)(121)Square root of (484) = Sq. root (4 x 121) = Sq. root (4) x sq. root of (121) = 2(11) = 22
11 units. (It is the square root of 121, and A=S^2 => 121=S^2 => S=11.)
The square root of 121 is the number which multiplied by itself will give 121, the answer is 11. (11*11=121). we write 11*11 as 112 thus if 112 = 121, then the square root of 121 or √121= 11 as you can see a square root of a number is the opposite of the square of a number
1 square root of 144 =12 square root of 121=11so 12-11=1
The square root of 121 is 11 which is not an irrational number.
Yes, the square root of 121 is 11
(10)2 = 100 (11)2 = 121 Since 114 is between 100 and 121, its square root must be between 10 and 11.
The square root of 121 is 11
The square root of 121 is rational, an integer, and a natural number.
121: ± 11625: ± 25
It is: 11
11