I believe you are referring to the technique of estimating a square root by division.
Step one: Find the nearest perfect square. 16 in this case.
step 2: Divide the number (15.625) by 4 (the square root of 16). The result is about 3.906
Step 3: Take the average of 4 and 3.906, which is 3.953. This is an approximation of the square root of 15.625.
by long division
The sixth root of 15625, or 15625 ^ (1/6) is equal to 5.
The square root of 32.50 is approximately 5.7. To find the square root, you can use a calculator or long division method. The square root of a number is a value that, when multiplied by itself, gives the original number.
The square root of 366,025 is 605. I don't know the division method, but that doesn't matter. The result is the same no matter what method you use to find it. If you work the same problem by two different methods and get two different answers, then at least one of them is wrong, and there's a good chance that they both are.
i don't kniw
The square root of 15625 is ±125 because 125 X 125= 15625.
The square root of 28224 is 168
The square root of 2304 is 48
by long division
i dont give a f***
The sixth root of 15625, or 15625 ^ (1/6) is equal to 5.
It is 36 because 1296/36 = 36
The square root of 32.50 is approximately 5.7. To find the square root, you can use a calculator or long division method. The square root of a number is a value that, when multiplied by itself, gives the original number.
To calculate the square root of 7.75 we use Hero's Method. By following Heroβs method we get: The square root of 7.75 = 2.7838 While round off 2.7838 to 3 Thus, the square root of 7.75 is 3 approximately
1) 125 is the square root of 15625. 2) √125 = √(25 x 5) = √(52x 5) = 5√5
We will walk through the definition of the square root of 63, find out whether the square root of 63 is rational or irrational, and see how to find the square root of 63 by the long division method. ... Square Root of 63.
The only significant difference that I know of is that there is a method, somewhat like long division, that can be used for finding the square root. I am not aware of a similar process for a cube root.