6 root(2) = root(36) root(2) = root(36 x 2) = root(72).
Square root of (1296) =Square root of (16 x 81)=SQ. root of (16) x Sq. root of (81) =4 x 9 =36
square root of 36 = 6 6 multiplied by 6 = 36 formula -> x2 = 36 (take square root of both sides) -> x = plus/minus 6
The square root of -36 is the square root of -1 times the square root of +36. The answer is 6i, where i is the square root of -1. This can be checked by the standard formula for two complex numbers: (a,b)x(c,d) = (ac-bd, ad+bc) (0,6) x (0,6) = (0x0 - 6x6, 0x6 + 6x0) = (-36, 0) or just -36.
the square root of x8 is x4
Square: 36 x 36 = 1296 Square root: √36 = 6
The square root of x squared is x, or x to the first power.
6 root(2) = root(36) root(2) = root(36 x 2) = root(72).
Square root of (1296) =Square root of (16 x 81)=SQ. root of (16) x Sq. root of (81) =4 x 9 =36
The square root of x = x to the power of a half
The square root of x to the seventeenth power is x to the eighth and a half power. If x is negative, the answer is imaginary.
square root of 36 = 6 6 multiplied by 6 = 36 formula -> x2 = 36 (take square root of both sides) -> x = plus/minus 6
36 x 6 = 216
The square root of -36 is the square root of -1 times the square root of +36. The answer is 6i, where i is the square root of -1. This can be checked by the standard formula for two complex numbers: (a,b)x(c,d) = (ac-bd, ad+bc) (0,6) x (0,6) = (0x0 - 6x6, 0x6 + 6x0) = (-36, 0) or just -36.
The square root of x to the 10th power is x to the 10th power raised to the 1/2 power, which simplifies to x to the 10/2 power. This further simplifies to x to the 5th power. Therefore, the square root of x to the 10th power is x to the 5th power.
The negative square root of a number is expressed as -√n or -n^½. The question probably may refer to the square root of a negative number. In mathematics there is an identity i² = -1 so that i = √-1 The square root of a negative number can be shown in several ways. For Example : √-36 = √( -1 x 36) = √-1 x √36 The square root of 36 is ±6, and the square root of -1 is i. The solution to √-36 is therefore ±6i.
the square root of x8 is x4