0.001
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The standard algorithm is long division. For this kind of division where the divisor (2926) is (much) greater than the dividend (3) I would recommend the Bus Stop method and to do the subtractions in full.
Start by writing the divisor outside the Bus Stop (shelter) and the 3 inside the Bus Stop. It is going to be less than 1, so I would immediately write a decimal point after the 3 in the dividend and in the quotient (directly over the decimal point in the dividend), and then put quite a few zeros after the decimal point in the dividend (as they do not change the dividend):
________.__________
______---------------
2029|3.00000000
Now follow the long division as normal, bringing down as usual:
_______0.00149___
______---------------
2029|3.00000000
_______2029
_______------
________9710
________8116
________------
_________5940
_________4058
_________------
_________18820
_________18261
_________--------
____________659
etc, repeating until the required accuracy is achieved. In this case as 659 is less than half of 2029, thus 3 ÷ 2029 is 0.00149 to 3 sig fig.
There are no separate algorithms for every possible division - you will use the same algorithm for any division (at least, of a certain class of numbers, such as whole numbers, or decimal numbers). The algorithm is the same; only the specific numbers change.You can find a description of how this algorithm works in math school books; or check the Wikipedia article on "Long division".
The full Question...Suppose 3 algorithms are used to perform the same task for a certain number of cycles. Algorithm A completes 3 cycles in one minute. Each of Algorithm B and Algorithm C respectively completes 4 and 5 cycles per minute. What is the shortest time required for each Algorithm to complete the same number of cycles?
((72 divided by 8) divided by 3) divided by 3 = 1
1 3 DIVIDED by 3 time 4 divided by 4, 3 time 4 = 12 divided by 4 = 3 then 3 divided by 3 equals 1
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