The integers 2 and 10 have a product of 20 and a sum of 12.
9 and 8
9 x 3 = 27 9 + 3 = 12
Formula:A (First Number) + B (Second Number) = C (Sum) C / 2 + 2B = APlugging the Numbers In:A + B = 72 72/2 + 2B = A 36 + 2B = AProof:60 + 12 = 72 60 - 12 = 48*** 60 & 12 ***
Sum: 16 Product: 48 Difference: 8 Quotient: 3
The answer is 12. 12x6=72 12+60=72
12(6 + 5)
24 + 48 = (2 x 12) + (4 x 12) = 6 x 12 = 72
The integers 2 and 10 have a product of 20 and a sum of 12.
Product = 35 Sum = 12
6 + 0 + 36 = 42
The factor pairs of 72 are (72,1)(36,2)(24,3)(18,4)(12,6)(9,8) None of them total 6. If that was -72, you could use 12 and -6.
9 and 8
24
72
6 and 2 are a number pair with a sum of 8 and a product of 12
Two integers that have a sum of -7 and a product of 12 are -3 and -4.