To find the sum of 5 and 8, you add them together: 5 + 8 = 13. To divide this sum by 2, you perform the operation 13 ÷ 2 = 6.5. Therefore, the result of summing 5 and 8 and then dividing by 2 is 6.5.
find the sum and product of the roots of 8×2+4×+5=0
Simplify the denominators and divide the numerators. Example: 8/5 ÷ 2/5 = 8/2 = 4 Check: 8/5 ÷ 2/5 = 8/5 x 5/2 = 8/2 = 4
5 and 8
To solve this problem, we first calculate the sum of 2 tens and 10 twos: 2 tens = 20, 10 twos = 20, so the sum is 20 + 20 = 40. Next, we determine how many fives are equal to 40 by dividing 40 by 5, which equals 8. Therefore, there are 8 fives that have the same value as the sum of 2 tens and 10 twos.
2.0
Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5
find the sum and product of the roots of 8×2+4×+5=0
Simplify the denominators and divide the numerators. Example: 8/5 ÷ 2/5 = 8/2 = 4 Check: 8/5 ÷ 2/5 = 8/5 x 5/2 = 8/2 = 4
5 and 3 5 + 3 = 8 5 - 3 = 2
2(8 + 5) = 2(13) = 26
The expression for 8 minus the sum of 5 and 43 divided by 8 can be written as: 8 - (5 + 43) / 8. First, calculate the sum inside the parentheses: 5 + 43 = 48. Then, divide 48 by 8 to get 6. Finally, subtract 6 from 8 to get the final result, which is 2.
Sum the number and divide the answer by the number of values that were added together.
It is the negative of the sum of the two positive equivalents. For example, (-5) + (-8) = -[5 + 8] = -13
3 & 5
The sum of 8 and 2 is 10
to sum two numbers you add them together then to get twice that you multiply the sum by 2 e.g. if the two numbers are 5 and 8 the sum = 5 + 8 = 13 twice that is 13 x 2 = 26
5,-3 5+(-3)=2 5-(-3)=5+3=8