To find the sum of 5 and 8, you add them together: 5 + 8 = 13. To divide this sum by 2, you perform the operation 13 ÷ 2 = 6.5. Therefore, the result of summing 5 and 8 and then dividing by 2 is 6.5.
find the sum and product of the roots of 8×2+4×+5=0
Simplify the denominators and divide the numerators. Example: 8/5 ÷ 2/5 = 8/2 = 4 Check: 8/5 ÷ 2/5 = 8/5 x 5/2 = 8/2 = 4
To solve this problem, we first calculate the sum of 2 tens and 10 twos: 2 tens = 20, 10 twos = 20, so the sum is 20 + 20 = 40. Next, we determine how many fives are equal to 40 by dividing 40 by 5, which equals 8. Therefore, there are 8 fives that have the same value as the sum of 2 tens and 10 twos.
5 and 8
2.0
Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5
find the sum and product of the roots of 8×2+4×+5=0
Simplify the denominators and divide the numerators. Example: 8/5 ÷ 2/5 = 8/2 = 4 Check: 8/5 ÷ 2/5 = 8/5 x 5/2 = 8/2 = 4
5 and 3 5 + 3 = 8 5 - 3 = 2
The expression for 8 minus the sum of 5 and 43 divided by 8 can be written as: 8 - (5 + 43) / 8. First, calculate the sum inside the parentheses: 5 + 43 = 48. Then, divide 48 by 8 to get 6. Finally, subtract 6 from 8 to get the final result, which is 2.
2(8 + 5) = 2(13) = 26
Sum the number and divide the answer by the number of values that were added together.
It is the negative of the sum of the two positive equivalents. For example, (-5) + (-8) = -[5 + 8] = -13
3 & 5
The sum of 8 and 2 is 10
to sum two numbers you add them together then to get twice that you multiply the sum by 2 e.g. if the two numbers are 5 and 8 the sum = 5 + 8 = 13 twice that is 13 x 2 = 26
5,-3 5+(-3)=2 5-(-3)=5+3=8