The sum of 1 + 8 is 9.
20
33 = 9 + 11 + 13
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
8+y is the sum of 8 and y
If you mean: -9-10+8 then their sum is -11
8/11 + 3/9 8/11 + 3/9
6 + 7 + 8 + 9 + 10 + 11 = 51
10, 9, 8, 7, 6 or 11, 9, 8, 7, 5 etc
The sum of 1 + 8 is 9.
11. Sum means to add 3+8=11
The numbers are -11, -10, -9 and -8.
The mean of these, or any group of ten numbers, is 1/10th of their sum.
-8-9-10-11 = -38
The sum of 9, 11, and 35 is calculated by adding these numbers together: 9 + 11 + 35 = 55. This is because addition is a basic arithmetic operation where you combine numbers to find the total. In this case, the sum of 9, 11, and 35 is 55.
20
The sum of 9 and the product of 8 is calculated by first finding the product of 8, which is 8. Then, adding 9 to this product results in a sum of 17. Therefore, the sum of 9 and the product of 8 is 17.