There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
195
2/5 + 2/4 = 9/10 9/10
4+5=9
The average (arithmetic mean) is the sum of the values divided by the number of values.Example : 5, 9, 10Their sum is 5+9+10 = 24 and there are 3 numbersThe average is 24/3 = 8
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
The sum of those fractions is 9 over 10 or 9/10.
195
If by "smaller than ten" you mean closer to zero than 10, then sum = -9 + -7 + ... + -1 + 1 + ... + 7 + 9 = 0 If you mean the numbers less than 10, then: sum = 9 + 7 + ... + 1 + -1 + -3 + ... = -∞ If you mean the counting numbers less than 10, then: sum = 1 + 3 + 5 + 7 + 9 = ½ × 5 × (1 + 9) = ½ × 5 × 10 = 25
Sum = 69Count = 10So mean = sum/count = 69/10 = 6.9Sum = 69Count = 10So mean = sum/count = 69/10 = 6.9Sum = 69Count = 10So mean = sum/count = 69/10 = 6.9Sum = 69Count = 10So mean = sum/count = 69/10 = 6.9
2/5 + 2/4 = 9/10 9/10
5,6,2,3,9 has a greater sum than 10,4,5,1 and 2 which has a sum of 22.
9 2/5 + 10 3/10 9 4/10 + 10 3/10 = 19 7/10
10, 9, 8, 7, 6 or 11, 9, 8, 7, 5 etc
The sum of 1/2 and 2/5 is 9/10
5 + 9 = 14
4 + 5 = 9 4 and 5 are two numbers with the sum of 9 and have a difference of 5