425
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
195
2/5 + 2/4 = 9/10 9/10
4+5=9
To determine if 235 is divisible by 9, we sum its digits: 2 + 3 + 5 = 10. Since 10 is not divisible by 9, 235 is not divisible by 9. In order for a number to be divisible by 9, the sum of its digits must be divisible by 9.
There is no sequence of adds or subtracts of 5, 6, 8, 9, and 10 that sum to 1. Check it with this C++ code... for (int i=0; i<32; ++i) { int sum = 0; if (i&1) sum += 5; else sum -= 5; if (i&2) sum += 6; else sum -= 6; if (i&4) sum += 8; else sum -= 8; if (i&8) sum += 9; else sum -= 9; if (i&16) sum += 10; else sum -= 10; cout << i << " " << sum << endl; }
The sum of those fractions is 9 over 10 or 9/10.
195
If by "smaller than ten" you mean closer to zero than 10, then sum = -9 + -7 + ... + -1 + 1 + ... + 7 + 9 = 0 If you mean the numbers less than 10, then: sum = 9 + 7 + ... + 1 + -1 + -3 + ... = -∞ If you mean the counting numbers less than 10, then: sum = 1 + 3 + 5 + 7 + 9 = ½ × 5 × (1 + 9) = ½ × 5 × 10 = 25
Sum = 69Count = 10So mean = sum/count = 69/10 = 6.9Sum = 69Count = 10So mean = sum/count = 69/10 = 6.9Sum = 69Count = 10So mean = sum/count = 69/10 = 6.9Sum = 69Count = 10So mean = sum/count = 69/10 = 6.9
2/5 + 2/4 = 9/10 9/10
5,6,2,3,9 has a greater sum than 10,4,5,1 and 2 which has a sum of 22.
10, 9, 8, 7, 6 or 11, 9, 8, 7, 5 etc
9 2/5 + 10 3/10 9 4/10 + 10 3/10 = 19 7/10
The sum of 1/2 and 2/5 is 9/10
5 + 9 = 14
4 + 5 = 9 4 and 5 are two numbers with the sum of 9 and have a difference of 5