You cannot. The sum of 5 odd numbers must be odd.
The numbers are -26, -24, and -22. (all negative numbers can be considered odd or even).
The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
the only two odd numbers are 57 and 59 which give a sum of 116
You cannot. 5 odd numbers must sum to an odd number. 26 is an even number.
The sum of the numbers is 26. The numbers are 12 and 14.
Prime numbers can only be odd, otherwise they'd be divisible by two, and thus not prime. But, as an example: 1 x 3 x 5 x 7= 105. (odd) An odd times an odd is always odd. Since primes are by definition odd, one cannot multiply four prime numbers and get anything other than an odd number, as each step produces an odd number. Thus a multiplicative sum of four primes is always odd. If by a sum you actually mean addition, then anytime you add two odd numbeers you get an even number, so any four prime numbers will give you an even result every time, and one answer is above. I assume you are only dealing with real numbers.Another Answer:Except for the number 2, which is even and prime, all prime numbers are odd. The sum of any two odd numbers is even, and the sum of any two even numbers is even, so the sum of any four odd numbers is also even. There are an infinite number of even numbers that can be written as the sum of four odd prime numbers. The first example is 3 + 5 + 7 + 11 which equals 26 or, in the full case, 3 + 3+ 3 + 3 which equals 18.
The sum of 7 and 19 is 26.
There are 52/2=26 even numbers in 52. Hence there are 26 odd numbers in 52, since 1 the first number is odd. You also get 26 if you count them: 1,3,5, ... 51.
Even. All numbers ending in six are even.