To find the sum of all numbers from 51 to 150, we can use the formula for the sum of an arithmetic series: (n/2)(first term + last term), where n is the number of terms. In this case, the first term is 51, the last term is 150, and the number of terms is 150 - 51 + 1 = 100. Plugging these values into the formula, we get (100/2)(51 + 150) = 50 * 201 = 10,050. Therefore, the sum of all numbers from 51 to 150 is 10,050.
The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
The sum of the first 10 counting numbers (1-10) is 51.
Let's denote the three consecutive numbers as x, x+1, and x+2. Since the sum of these three numbers is 150, we can write the equation x + (x+1) + (x+2) = 150. Simplifying this equation gives us 3x + 3 = 150. Solving for x, we get x = 49. Therefore, the three consecutive numbers are 49, 50, and 51.
there is 99
16 and 35
The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
51
The sum of the first 10 counting numbers (1-10) is 51.
They are: 49+50+51 = 150
A sum has to include two or more numbers in the calculation.
Let's denote the three consecutive numbers as x, x+1, and x+2. Since the sum of these three numbers is 150, we can write the equation x + (x+1) + (x+2) = 150. Simplifying this equation gives us 3x + 3 = 150. Solving for x, we get x = 49. Therefore, the three consecutive numbers are 49, 50, and 51.
there is 99
16 and 35
The sum of the four given numbers is -13.
15,17,19
The numbers are 51, 52 and 53.
The numbers are 15, 17, and 19.