This is an arithmetic series, so we use the formula S=n/2 (a+l) when n is the number of terms, a is the first number and l the last.
S = 100/2 (51 + 150) =50 (201) = 10050
You can use the formula for the sum of an arithmetic series for this type of question.
The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
The sum of the first 10 counting numbers (1-10) is 51.
there is 99
16 and 35
The numbers are 51, 52 and 53.
The sum of the numbers between 51 and 150 is equal to 10050 - or 50 x 201 - as there are 50 lots of 201 in the sum.
51
The sum of the first 10 counting numbers (1-10) is 51.
They are: 49+50+51 = 150
A sum has to include two or more numbers in the calculation.
16 and 35
there is 99
The sum of the four given numbers is -13.
240
15,17,19
The numbers are 51, 52 and 53.
The numbers are 50, 51, and 52.