It's all based on what you tesselate. If 360 degrees makes a full circle or rotation, then you know that for every vertex intersecting it is 360 divided by the quantity of vertexes.
For example, if we had a tesselation of only triangles, we would have 6 vertexes. We know this because it takes 6 equilateral triangles to make a hexagon.
So, we simply do 360, which are the degrees we have to go around, divided by 6, the total vertices (the plural of vertex), we would get 60. We know this is true because the sum of the degrees in all vertices in a triangle HAS to be 180.
In a tessellation, the angle sum around a vertex depends on the type of polygons used in the tessellation. For regular polygons, the angle sum around a vertex is always 360 degrees. This is because each interior angle of a regular polygon is the same, so when multiple regular polygons meet at a vertex in a tessellation, the angles add up to 360 degrees.
each side of a angle is a vertex * * * * * No, the point where the sides meet is the vertex. The sides themselves are ... just sides.
Each angle in an equilateral triangle is 60 degrees. In order to create a regular tessellation of an area, we need for the angles of the polygons we are putting near each other to sum to 360 degrees. If you place six equilateral triangles so that all of them share a vertex, and each triangle is adjacent to two others, you get 60*6 = 360 degrees in that vertex. Please see related link for a demo of a triangular tessellation.
If it's a regular polygon: 360/number of sides = each exterior angle
Theorem 6-1-2; Polygon Exterior Angle Sum Theorem:The sum of the exterior angle measures, one angle at each vertex, of a convex polygon is 360 degrees.
In a tessellation, the angle sum around a vertex depends on the type of polygons used in the tessellation. For regular polygons, the angle sum around a vertex is always 360 degrees. This is because each interior angle of a regular polygon is the same, so when multiple regular polygons meet at a vertex in a tessellation, the angles add up to 360 degrees.
The vertex angle of an isosceles triangle is equal to the measure of each of its base angles. Therefore, if one of the base angles measures 42 degrees, then the vertex angle also measures 42 degrees.
Each base angle is 62.5 degrees
Its 2 equal base angles will each measure 65 degrees
Every angle has a vertex. A vertex is simply the line through the center of each angle. The line splits the angle exactly in half.
An angle is formed at each vertex of a polygon.
The measure of each base angle in an isosceles triangle can be calculated by dividing the total angle sum by the number of base angles, i.e., (180 - vertex angle) / 2. In this case, each base angle of the isosceles triangle would measure (180 - 38) / 2 = 71 degrees.
each side of a angle is a vertex * * * * * No, the point where the sides meet is the vertex. The sides themselves are ... just sides.
Each interior angle of a regular heptagon measures 900/7 degrees.The interior angles of all polygons meeting at a point must sum to 360 degrees. But that would require 360 / (900/7) = 2.8 - that is you would require 2.8 regular heptagons to meet at each vertex. Since it is not possible to have a fraction of a heptagon. the tessellation required by the question is impossible.
Each angle in an equilateral triangle is 60 degrees. In order to create a regular tessellation of an area, we need for the angles of the polygons we are putting near each other to sum to 360 degrees. If you place six equilateral triangles so that all of them share a vertex, and each triangle is adjacent to two others, you get 60*6 = 360 degrees in that vertex. Please see related link for a demo of a triangular tessellation.
If it's a regular polygon: 360/number of sides = each exterior angle
the measures of each angle in a dodecogon is 360