The sum of the digits will be divisible by 3 if the number itself is divisible by 3.
Examples:
3999 -> 3 + 9 + 9 + 9 = 30
126 -> 1 + 2 + 6 = 9
6012 -> 6 + 1 + 2 = 9
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513 is divisible by 3 because the sum of its digits is a multiple of 3. 171 is divisible by 3 because the sum of its digits is a multiple of 3. 57 is divisible by 3 because the sum of its digits is a multiple of 3. 3 x 3 x 3 x 19 = 513
no because the sum of the digits needs to be a multiple of 3.
you add up the digits, and if the sum is a multiple of 3, then the number is divisible by 3!
Oh, dude, a factor of the sum of the digits being 3 or a multiple of 3 just means that if you add up all the digits in a number and it equals 3, or if that sum is a multiple of 3, then that number has a factor that fits the bill. So, like, if you have a number where the digits add up to 3, or 6, or 9, or any multiple of 3, you've got yourself a match! It's like finding a snack in your pantry that fits your cravings perfectly – it just works out, man.
A number is divisible by 3 if the sum of its digits is a multiple of 3. For example, 27 = 2 + 7 = 9/3 = 3. Therefore, 27 is divisible by 3.If the sum of the digits of the number in question is divisible by three, the whole number is divisible by three.