The sum of the first 5,000 odd numbers is 25,000,000 (25 million). This is an easy calculation. Simply square the number of integers you are looking to calculate. In this case 5,000 squared = 5,000 x 5,000 = 25 million.
I assume the question refer to the sum of positive odd numbers up to 25. If so, the answer is 169. If not, please resubmit your question stating exactly what you require.
The sum of all odd numbers, up to the odd number (2n-1) is n^2. So the sum of the first 1000 or 10^3 odd positive numbers is (10^3)^2=10^6 Now divide by 10^3 or 1000 since we have 1000 numbers so we have 10^6/10^3=1000 The mean of the first 1000 positive odd numbers is 1000 If you ask the mean of the odd numbers between, 1 and 1000, that is another problem, since there are 500 of them, the answer would be 500^2/500=500 Think of the mean of the odd numbers between 1 and 10, there are 5 of them and there sum is 25 so the mean is 25/5 or 5 **** in general, the arithmetic mean of the first n odd numbers is n^2/n or n. So that is why the number is 1000.
The answer for the first 30 odd numbers (1,3,5,7,9,11,13,15,17,19,21,23,25,27,29,31,33,35,37,39,41,43,45,47,49,51,53,55,57,59) is 995.Actually, the sum of the first 30 odd numbers is 900.1+3+5+7+9+11+13+15+17+19+21+23+25+27+29+31+33+35+37+39+41+43+45+47+49+51+53+55+57+59 = 900
The sum of the first 25 numbers is 25*26/2 = 325 So the sum of the first 25 multiples of 12 is 325*12 = 3900
The sum of the first n odd numbers is n squared. 25 x 25 = 625
No two odd numbers can sum to 7.
The sum of the first 5,000 odd numbers is 25,000,000 (25 million). This is an easy calculation. Simply square the number of integers you are looking to calculate. In this case 5,000 squared = 5,000 x 5,000 = 25 million.
All odd numbers are the sum of two consecutive numbers. Odd multiples of 7 less than 25 are 7 and 21.
1+3+5+7+9=25
The sum of the first 25 prime numbers is 1,060.
25
The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
I assume the question refer to the sum of positive odd numbers up to 25. If so, the answer is 169. If not, please resubmit your question stating exactly what you require.
Yes. The sum of the first 5,000 odd, positive integers is 25,000,000 (25 million).
Oh, what a happy little question! Let's take a look at those prime numbers. When we add them up, we find that their sum is actually even. Isn't that just a delightful surprise? Remember, in the world of numbers, there's always a little bit of magic waiting to be discovered.
25 of them