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Sum of first n natural numbers is (n) x (n + 1)/2

Here we have the sum = 100 x (101)/2 = 50 x 101 = 5050

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Q: What is the sum of the numbers from 1 to 100?
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What is the Sum of the numbers from 1 through 100?

The sum of the numbers from 1 through 100 is 5,050.


What is the sum of the whole numbers from 1 to 100 inclusive?

The sum of the whole numbers from 1 to 100 inclusive is 5,050.


Sum the numbers from 1-100?

101


Sum of the all prime numbers within 1 to 100?

The sum of the all prime numbers from 1 to 100 is 1,161


What is the sum from all the odd numbers from 1 to 100?

The sum of all the odd numbers from 1 through 100 is 10,000


What is the sum of the first 100 even numbers?

n*(n+1)=sum 100*(100+1)=10100


Hoe can you write a programme to claculate 1 plus 2 plus 3..100?

You add the numbers in a loop. Here is an example in Java:int sum = 0;for (int i = 1; i


What do the numbers 1 through 100 equal too?

The sum of the numbers 1 to 100 is 5050.


What is the sum of all composite numbers from 1 to 100?

The sum of these composite numbers, including 100, is 3989.The sum of all numbers between 1 and 100 is 5,050. From this we need to subtract the sum of 1 plus all the prime numbers below 100. The sum of the primes is 1,060. Subtracting (1 + 1060) or 1,061 from 5,050 yields 3,989.


What is the sum the first 100 counting number?

The sum of the first 100 counting numbers (1-100) is 5,001.


What is the sum of all numbers numbers from 1-100?

101


What is the difference between the sum of all even numbers and odd numbers from 25 to 100?

The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.