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(8*4) + (8-4) = 32 + 4 = 36

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Q: What is the sum of the product and difference of 8 and 4?

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Sum: 16 Product: 48 Difference: 8 Quotient: 3

The sum of 8 and 5 is 13 The difference of 8 and 5 is 3 So the question is what is the product of 13 and 3 13 X 3= 39

Sum of 8 and 4 (8+4=12) is 12 Difference of 8 and 4 (8-4=4) is 4 So 12/4 is 3

two real numbers, whose sum is 8 and product is max, are 4,4. 4+4=8 and 4*4=16.

8+4 = 12 and 8-4 = 4

Related questions

Sum: 16 Product: 48 Difference: 8 Quotient: 3

Sum: 16 Product: 48 Difference: 8 Quotient: 3

The answer is -32 Sum of -16+8 = -8 Half of -8 = -4 Sum of -5+9 = 4 Twice of 4 = 8 Product = 8*(-4) = -32

The sum of 8 and 5 is 13 The difference of 8 and 5 is 3 So the question is what is the product of 13 and 3 13 X 3= 39

80 is.

Sum of 8 and 4 (8+4=12) is 12 Difference of 8 and 4 (8-4=4) is 4 So 12/4 is 3

well the sum would be 4+8=12 the difference would be 8-4=4 so multiply those and you get 4x12=48

two real numbers, whose sum is 8 and product is max, are 4,4. 4+4=8 and 4*4=16.

8+4 = 12 and 8-4 = 4

The sum of 20 and -4 is +16, while the product of 4 and -2 is -8. The answer to the question is therefore -2.

find the sum and product of the roots of 8×2+4×+5=0

8