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The surface area of a prism is twice the area of the end plus the area of all the sides.

For a prism with a polygon cross-section the area of all the sides if given by the perimeter of the cross-section polygon multiplied by the length of the prism.

Assuming you have a prism of cross-section that is a rectangle with sides 4 mm and 3 mm, and is 15 mm long (ie it is an oblong), its surface area is:

→ surface_area = 2 × (4 mm × 3 mm) + 2 × (4 mm + 3 mm) × 15 mm

→ surface area = 2 × 12 mm² + 14 mm × 15 mm = 234 mm²

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Find the surface area of a rectangular prism that has the following dimensions length 2 ft width 14 in height 11 in?

Designating the prism's length by l, the prism's width by w, and the prism's height by h, the general formula is 2lw+2lh+2hw, because there are two surfaces that are rectangles with length and width of the prism's length and width, two surfaces that are rectangles with length and width that are the prism's length and height, and two surfaces that are rectangles with length and width that are the prism's width and height. To give all dimensions the same units, multiply the 2 foot width by 12 in/ft to yield 24 inches Applying the formula yields: (2 X 24 X 14) + (2 X 24 X 11) + (2 X 11 X 14) = 1508 square inches.


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Related Questions

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