Surface area of a rectangular prism is equal to 2LW+2LH+2HW. So for this object: 2*3*4+2*3*8+2*8*4=24+48+64=136 square inches.
volume = 3in x 3in x 3in = 27in3
Well, isn't that a happy little question! To find the surface area of a cube, you simply need to calculate the area of all six sides and add them up. Since all sides of a cube are the same, you can find the area of one side by squaring the length of one side. So, for a 3-inch cube, the surface area would be 6 sides x (3 inches x 3 inches), which equals 54 square inches. Happy painting!
One 9 inch square tile would presumably be 9in x 9in or 81in2, unless you are meaning 3in x 3in tile which is then 9in2. Regardless, the answer to your question is the total area of the floor (in square inches) divided by the total area of one tile (in square inches).
63 inches
190.5 cm
136 in.
It is: 2(3*5)+2(3*8)+2(5*8) = 158 square inches
Break it down into parts and then add together all the areas which are:- 15+15+24+24+40+40 = 158 square inches
90 cubic inches.
45 cubes I believe
(2 x 3 x 4) + (2 x 3 x 6.5) + (2 x 4 x 6.5) = 24 + 39 + 52 = 115 square inches
A cylinder with a radius of 7in and a length of 3in has a total surface area of about 439.82 square inches.
Total surface area is 439.82 square inches.
6*9 = 54 square inches
Help
first you multiply each side by 1,000,000 then you find the surface area of a cylinder that has a diameter of 3in and the height of 6in
Base x Height.... The base of a cylinder is a circle. So you first find the area of the circle. pi times the radius squared. (for example, with a cylinder with a radius of 2in and a height of 3in, the area of the base would be about 2 x 2 x 3.14 = 12.56 Then you multiply the area of the base with the height. So going with our example, 12.56 x 3 = 37.68 inches. Think about it this way: The volume of a rectangular prism is length x width x height. The base of a rectangular prism is a rectangle , and to find the area of that is length x width. So it's the area of the base (which is length x width) x the height.