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22 cm squared

5 x 1 = 5 [one side 5 cubes long 1 cube high]

5 x 4 = 20 [4 sides]

1 x 1 = 1 [one end of cube]

1 x 2 = 2 [both ends of cube]

20 + 2 = 22

* * * * *

If there are no partially attached faces, the maximum area is 22 cm2 as above. But a 2x2 square arrangement, with the fifth cube attached anywhere gives 20 cm2.

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Q: What is the surface area of five 1cm cubes stuck together?
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