Consider going across the width of the pipe:
Outer diameter = Thickness + Inner diameter + Thickness
so 2*Thickness = Outer diameter - Inner diameter = 2.5 - 2.1 = 0.4 inches
and therefore, Thickness = 0.2 inches.
The mass of a pipe depends on four variables: ¨ the material it is made from, ¨ its length ¨ its outer diameter ¨ the thickness of the material. The inner diameter can replace the thickness. Without information on all four it is not possible to answer the question. There is no information on the thickness of the material.
Depends on if the 10" is inner or outer diameter, and the length of the pipe.
151
"Solid Steel" would not be a pipe- it would be a rod. Weight of pipe will vary depending on the thickness of the wall of the pipe.
What is the maximum flow rate of a two inches in diameter of a pipe in cubic meter per hour?ImprovecapitalOneround('alternateMsg');
The wall thickness of 4" Sch 40 pipe is 0.237 inches.The outer diameter is 4.5 inches and the inner diameter is 4.026 inches.
That would depend on the wall thickness of the pipe. 54 inches is the outside diameter so subtract the pipe wall thickness (x2) adn you have the inside diameter.
bore of the pipe is the internal diameter of pipe but the nominal diameter of pipe is the dia of a circle which is draw through a point which is situates at exactly half of the thickness of pipe or we can say that (outer dia of pipe- thickness of pipe )=nominal bore of pipe.
The inside diameter (ID) is 8 inches. The nominal pipe size (NPS) and outside diameter (OD) depend on the thickness of the walls of the pipe.
Outer radius minus inner radius Subtract the inside diameter from the outside diameter, then divide the difference by 2.
Then the wall thickness is 1 inch
Can you calculate the ID of a pipe when you have the OD to be 10.75" and the wall thickness to be 0.5"Depends on what you know about it. If you have the outer diameter and you know the wall thickness, then ID = OD-2 x wall thickness
30-inch (inside diameter) RCP has a wall thickness of 2.75 inches. Therefore, the outside diameter of 30-inch RCP is 35.5 inches.
take the outside diameter and subtract the thickness twice.
take the outside diameter and subtract the thickness twice.
take the outside diameter and subtract the thickness twice.
The answer is the difference between the radii of the inner circumscribed circle and the outer circumscribed circle. The radii equal half of the corresponding diameters; therefore, the thickness is 1/2(2.84 - 1.94) = 0.450 inches, where the last digit is depressed because it may not be accurate within + 1. (The difference between 2.84 and 1.94 has only two significant digits.)