What is the three consecutive whole number of sum 492?

Answer 1

163, 164, 165

let the three consecutive numbers be (n-1), n & (n+1). Then:

(n-1) + n + (n+1) = 492

⇒ 3n = 492

⇒ n = 164

⇒ the three numbers are 164-1 = 163, 164 & 164+1 = 165.