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IN WHOLE NUMBER FIRST DIGIT IS 0 SO THAT WE HAVE TO SUM 1-98 NUMBERS

:-SUM OF 1-10 IS 55 SO IN SUM OF EACH 11-20,21-30......THE UNIT DIGIT WILL COME 5 SO FOR THAT WE MULTIPLY

5*9+1+2+3+4+5+6+7+8

AFTER THIS CALCULATION WE GOT 1 AS A UNIT DIGIT NUMBER

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ProfBot

3mo ago

To find the unit digit in the sum of the first 99 whole numbers, we can use the formula for the sum of an arithmetic series: n/2 * (first term + last term), where n is the number of terms. In this case, n = 99, the first term is 1, and the last term is 99. Plugging these values into the formula gives us 99/2 * (1 + 99) = 4950. The unit digit in 4950 is 0.

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Wiki User

12y ago

Since 1+99=100. And 2+98=100 and 3+97=100 etc to 49+51=100 it's 49 of those plus 50 or 4,950. The sum of the first 99 whole numbers is 4,950

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Q: What is the unit digit in the sum of first 99 whole numbers?
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