IN WHOLE NUMBER FIRST DIGIT IS 0 SO THAT WE HAVE TO SUM 1-98 NUMBERS
:-SUM OF 1-10 IS 55 SO IN SUM OF EACH 11-20,21-30......THE UNIT DIGIT WILL COME 5 SO FOR THAT WE MULTIPLY
5*9+1+2+3+4+5+6+7+8
AFTER THIS CALCULATION WE GOT 1 AS A UNIT DIGIT NUMBER
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To find the unit digit in the sum of the first 99 whole numbers, we can use the formula for the sum of an arithmetic series: n/2 * (first term + last term), where n is the number of terms. In this case, n = 99, the first term is 1, and the last term is 99. Plugging these values into the formula gives us 99/2 * (1 + 99) = 4950. The unit digit in 4950 is 0.
Since 1+99=100. And 2+98=100 and 3+97=100 etc to 49+51=100 it's 49 of those plus 50 or 4,950. The sum of the first 99 whole numbers is 4,950
As 3844 ends in 4, its square root (if a whole number) will end in 2 or 8. √3844 = 62 so the unit digit is 2.
113.04 rounded to the nearest unit is 113. Take the last digit of the WHOLE number, in this case, the 3.
the unit digit is 4
Any digit in the tens or higher place has no influence on the answer. So it is the unit digit of 4*9*3*6 = unit digit of 6*3*6 = unit digit of 8*6 = 8
It is the first whole number divided by the denominator of the unit fraction. This could be a whole number or a fraction.