Q: What is the value of 2 x 0 x 1 plus 1?

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the answer is 0 because 1 times 1 is 1 plus 1 is 2 and 1 plus 1 is 2 so subtract 2 from 2 and that get 0

0=(9)2-(9-3)(root of 4)+3(2)

It is closer to 1 than it is to 0.

0

It is not possible to evaluate the expression without any operators.

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It equals 6

100101 1 times 2^0 = 1 PLUS 0 times 2^1 = 0 PLUS 1 times 2^2 = 4 PLUS 0 times 2^3 = 0 PLUS 0 times 2^4 = 0 PLUS 1 times 2^5 = 32 EQUALS 37

It is: (1+1)*(0+1) = 2

cos2x + 2sinx - 2 = 0 (1-2sin2x)+2sinx-2=0 -(2sin2x-2sinx+1)=0 -2sinx(sinx+1)=0 -2sinx=0 , sinx+1=0 sinx=0 , sinx=1 x= 0(pi) , pi/2 , pi

|x + 1| - |x + 4| = 0 ∴ |x + 1| = |x + 4| ∴ x + 1 = -x - 4 ∴ 2x = -5 ∴ x = -5/2

so easy... it is 5. even a toddler can answer it!

It is: 2x squared +5x -7 = 0 and the value of x = -7/2 or 1

the answer is 0 because 1 times 1 is 1 plus 1 is 2 and 1 plus 1 is 2 so subtract 2 from 2 and that get 0

Equation: x^2 +2kx +10x +k^2 +5 = 0 Using the discriminant: (2k +10)^2 -4*1*(k^2 +5) = 0 Solving the discriminant: k = -2

If: 6x^2 +2x +k = 0 has equal roots Then using the discriminant of b^2 -4ab=0: 4 -24k=0 => k=-4/-24 => k=1/6 Therefore the value of k = 1/6

The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).