6 thousands
The next number in the sequence will be 56.
Each number in the sequence is equal to the previous number increased by one.
To find the value of the nth term in an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference between terms. In this sequence, the first term (a_1 = 12) and the common difference (d = -6 - 0 = -6). So, the formula becomes (a_n = 12 + (n-1)(-6)). Simplifying this gives (a_n = 12 - 6n + 6). Therefore, the value of the nth term in this arithmetic sequence is (a_n = 18 - 6n).
-34
Its value is 6.
Without a sequence given in the question, the next number to 6 is 7.
48
691215 is not a sequence: it is a single 6-digit number.
A number sequence is not a question. So there can be no "answer".
The next number is 39. The position to value rule is: Un = (7n4 - 89n3 + 392n2 - 694n + 438)/6 for n = 1, 2, 3, ...
The next number in the sequence 3-15-6-30-21 is -207.
The next number in the sequence is 6. The sequence alternates between adding 3 and subtracting 1 from the previous number.
The next number in the sequence will be 56.
Each number in the sequence is equal to the previous number increased by one.
0
In the number 68345, the value of the 6 is 6000. The value of a digit in a number is determined by its place in the number. In this case, the 6 is in the thousands place, so its value is 6 x 1000 = 6000.
1