6 thousands
The next number in the sequence will be 56.
Each number in the sequence is equal to the previous number increased by one.
-34
To find the value of the nth term in an arithmetic sequence, you can use the formula: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference between terms. In this sequence, the first term (a_1 = 12) and the common difference (d = -6 - 0 = -6). So, the formula becomes (a_n = 12 + (n-1)(-6)). Simplifying this gives (a_n = 12 - 6n + 6). Therefore, the value of the nth term in this arithmetic sequence is (a_n = 18 - 6n).
Its value is 6.
Without a sequence given in the question, the next number to 6 is 7.
48
691215 is not a sequence: it is a single 6-digit number.
A number sequence is not a question. So there can be no "answer".
The next number is 39. The position to value rule is: Un = (7n4 - 89n3 + 392n2 - 694n + 438)/6 for n = 1, 2, 3, ...
The next number in the sequence 3-15-6-30-21 is -207.
The next number in the sequence is 6. The sequence alternates between adding 3 and subtracting 1 from the previous number.
The next number in the sequence will be 56.
Each number in the sequence is equal to the previous number increased by one.
0
In the number 68345, the value of the 6 is 6000. The value of a digit in a number is determined by its place in the number. In this case, the 6 is in the thousands place, so its value is 6 x 1000 = 6000.
1