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pKa+pKb=pKw=14

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Q: What is the value of pKw?
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What is the pH if pKw is 14.26?

I will assume you are asking about the pH of pure water if pKw is 14.26. The relationship between pH, pOH, and pKw is as follows: pH + pOH = pKw. If it is pure, neutral water (no acids or bases present), then pH = pOH, so: pH + pOH = 14.26 2(pH) = 14.26 pH = pOH = 7.13


Where is Sam's Club on cobb pkw in marietta ga?

there is not


How do you say red car in German?

red car = rotes Auto red car = roter Wagen red car = roter PKW


Where is the On The Chisholm Trail Association in Duncan Oklahoma located?

The address of the On The Chisholm Trail Association is: 1000 Chisholm Trail Pkw, Duncan, OK 73533-1539


Where can I find an industrial mixing equipment?

http://www.alfalaval.com/campaigns/tankequipment/mixing-and-agitation/product-overview/pages/product-overview.aspx?pkw=industrial%20mixing%20equipment is a website that you can find an industrial mixing equipment.


What is the pKw of water?

Here is the first step to convincing you that the pKa of water should not be 7: water is clearly a weaker acid than hydrogen sulfide, whose pKa is 7.04, or boric acid, 9.14, or hydrogen cyanide, 9.31 The real problem is why the pKa should not be 14.0 -- the same as pKw Here is the reason: Kw is defined as [H+]*[OH-], and this turns out to be 1.E-14. For any acid HA in water, though, Ka is defined as [H+]*[A-]/[HA] So if we think of water as an acid, Ka = [H+] * [OH-] / [H2O] = 1.0E-14 / [H2O] What do we do for [H2O]? Well, 1 g of water occupies 1 mL, near enough, which means that 18 gram of water = 1 mol of water occupies 18 mL. So we can fit 55.6 mol of pure water in 1.00 L. It is therefore fair to say that the "concentration" of water is 55.6 M, and so Ka = 1.8E-16 The log of 1.8E-16 to base 10 is -15.75, which is the pKa value quoted in your question.


Is it true that the sum of pka and pkb is always equal to 14 at all temperature for any acid?

In general, at 25°C the sum of pKa and pKb for a conjugate acid-base pair will equal 14 due to the auto-ionization of water. However, at different temperatures, the sum may vary slightly due to changes in the equilibrium constant of water ionization.


How do you use pka to find the pH value?

To find the pH value using pKa, you first need to identify the acid or base equilibrium involved in the reaction. Then, you can use the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]), where [A-] is the conjugate base concentration and [HA] is the acid concentration. By knowing the pKa value and the concentrations of the acid and its conjugate base, you can calculate the pH of the solution.


Calculate the pH of a 0.028 m NACN solution Ka 4.9 x 10 -10. the answer is 10.88 please help?

To find the pH of a solution of NaCN, you first need to calculate the concentration of CN- ions (0.028 M) using the molarity of NaCN. Then, calculate the concentration of H+ ions that CN- will react with. Finally, use the Ka value to find the concentration of H+ ions and convert it to pH using the formula pH = -log[H+]. The resulting pH is approximately 10.88 in this case.


How many times more hydroxide ions are there in a solution with a pH than in a solution with a pH of 3?

The concentration of hydroxide ion is realted to pH by the pKw (10-14) At pH 9 the concentration of OH- is 10-5, at pH 3, 10-11. The ratio is 106 so there are a million times as many OH- in pH 9.


How many more hydroxide ions are there in a solution with a pH of 9 than in a solution with a pH of 3?

The concentration of hydroxide ion is realted to pH by the pKw (10-14) At pH 9 the concentration of OH- is 10-5, at pH 3, 10-11. The ratio is 106 so there are a million times as many OH- in pH 9.


How many times more hydroxide ions are in a solution with a pH of 9 than in a solution with a pH of 3?

The concentration of hydroxide ion is realted to pH by the pKw (10-14) At pH 9 the concentration of OH- is 10-5, at pH 3, 10-11. The ratio is 106 so there are a million times as many OH- in pH 9.