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In order to answer that, you need to know how 'x' and 'y' are related to

each other. In the book that you copied this from, there was most likely

an equation with the question. It was there to show how they're related.

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What is the value of x for the equations x-y equals 120 and x plus y equals 150?

x-y = 120 x+y = 150 add equations: 2x = 270 x = 135 y = 15


What is the y value of x - y equals 120 x plus y equals 150?

15 (x = 135)


What is the value of y for the equations x-y equals 120 and x plus y equals 150?

15


What plus something equals 300?

To find what plus something equals 300, you can represent it mathematically as ( x + y = 300 ), where ( x ) is the known value and ( y ) is the unknown value. For example, if ( x ) is 150, then ( y ) would be 150, since ( 150 + 150 = 300 ). You can replace ( x ) with any number less than 300 to find the corresponding ( y ).


what does the slope represent y=10x + 150?

The slope of this equation is 10 and the y intercept is 150


What does x - y?

In expressions such as "x-y", both "x" and "y" can have any value. The value of "x-y" will depend on what the value of "x" and the value of "y" are.


The function y equals sin θ is not a function beacause sin 30 equals sin 150?

Y=sin X is a function because for each value of X, there is exactly one Y value.


Use addition or substitution to find the value of x for this set of equations for x - y equals 120 x plus y equals 150?

X = 135 and y = 15 Solved by addition and substitution


Rs. 49.25 was divided into 150 children Such that each boy got Rs. 0.25 and each girl Rs. 0.50 How many boys and girls are there?

Let x be the number of boys and y be the number of girls. That gives us two equations: x + y = 150 and .25x + .5y = 49.25. Solve the first equation for x: x = 150 - y. Plug that value of x into the second equation: .25(150 - y) + .5y = 49.25 Solve for y: 37.5 - .25y + .5y = 49.25, .25y = 11.75, y = 47. Thus, there are 47 girls. Plug this value back into the first equation to get the number of boys: x + 47 = 150, x = 103.


What is x - y 120 and x y 150?

If your system is x - y = 120 x + y = 150 I would use elimination. Adding the two equations together gives us 2x = 270 and dividing by two tells us that x = 135. Plug x back into either equation to find y: x + y = 150 135 + y = 150 y = 15 So x = 135 and y = 15.


Which two numbers which have a difference of 150 but add up to 1000?

Let the two numbers be (x) and (y). We have the equations (x - y = 150) and (x + y = 1000). Solving these simultaneously, we can express (x) in terms of (y): (x = y + 150). Substituting this into the second equation, we get (y + 150 + y = 1000), which simplifies to (2y + 150 = 1000). Solving for (y) gives (y = 425), and substituting back, (x = 575). The two numbers are 575 and 425.


If y varies directly as x squared and y equals 150 when x equals 5 find y when x equals 4?

First you need to know that the equation you are looking for is y = kx^2. Then you need to substitute the numbers in: y = kx^2 150 = k5^2 150 = k25 6 = k Now that you know k, resubstitute it for the new value of y when x = 4: y = kx^2 y = (6)(4)^2 y = (6)(16) y = 96