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It all depends upon the radius of the sphere, since:

volume_of_sphere = 4/3πr3

Once that has been calculated, the result is rounded using normal rounding rules - look at the tenths' digit and if it is less than 5 truncate the result to the whole number (ie ignore the decimal part) otherwise add 1 to the result truncated to a whole number.

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Q: What is the volume of a sphere with rounding to the nearest whole number?
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