(3, 2)
5m + 7 - 2m - 1 = 3m + 6
3x-5y=7 5x-2y=-1
If those are two different equations, such that 2y=5x-1 and x=y+2, then you subsitute y+2 in for x in the first equation, and when you solve the whole thing, you get that x=-1 and y=-3, or the point (-1,-3)
2x + 5y = 16 + (-5x) - 2y = 2 That gives 2x + 5y = 2 . . . . . . . . . . (I) and -5x - 2y = - 14 or 5x + 2y = 14 . . . . (II) (I)*5: 10x + 25y = 10 (II)*2: 10x + 4y = 28 Subtracting the second from the first, 21y = -18 so y = -18/21 = -6/7 and then by (I) x = 1 - 5y/2 = 1 - 5/2*(-6/7) = 1 + 15/7 = 22/7 So the ordered pair is (22/7, -6/7)
(3, 2)
x = 3 and y = 2
3x+2y=20 5x-2y=1 (3x+2y) + (5x-2y)= 20+1 3x+5x= 21....... 8x=21.........x=2 5/8 Subsitute x=3(2 5/8)+ 2y=20........... 7 7/8 +2y=20.........2y= 20- 7 7/8....... y=6 1/16
If you mean: 2y+5x = 13 and 2y-3x = 5 then x = 1 and y = 4
If you mean: 2y+5x = 13 and 2y-3x = 5 then it works out that x = 1 and y = 4
If you mean 5x+y = 21 and x = 6-2y then x = 4 and y = 1
For 5x+y=1, you would subtract 5x from each side, so you would get y=1-5x For 3x+2y=2, you would subtract 3x from each side, and then divide by 2. 2y=2-3x y=1-(3/2)x
5x+1=20 5x=20-1 5x=19 5x/5=19/5 x=19/5
x+2y = -1 and 5x-4y = 16 Solving the simultaneous equations gives: x = 2 and y = -1.5
There are two answers to this, because you did not give two equations. x = 1 and y = 7 x = 3 and y =1
Multiply the bottom equation by -1
(1, 1)