One important truth is that it is not balanced, because it has five chlorine atoms on the right side and only two chlorine atoms on the left. The equation should read:
2 FeCl2 + SnCl4 -> SnCl2 + 2 FeCl3. The equation also describes an oxidation-reduction reaction, in which iron ions are oxidized and tin ions are reduced.
function of SnCl2 is that it acts as a reducing agent to reduce FeCl3 to FeCl2 and function of HgCl2 is to oxidize SnCl2 to SnCl4. total iron is determined after reducing ferric iron to ferrous state.
When SnCl4 is heated, it undergoes thermal decomposition to form SnCl2 and Cl2 gases. The decomposition reaction is: 2 SnCl4 (s) -> 2 SnCl2 (s) + Cl2 (g)
SnCl2 is more stable than SnCl4 because of the lower oxidation state of tin (+2 in SnCl2 compared to +4 in SnCl4). The lower oxidation state of tin in SnCl2 leads to a higher stability due to less repulsion between the electrons. Additionally, the bond energy in the Sn-Cl bonds of SnCl2 is stronger than that in SnCl4, contributing to its stability.
The oxidation number of Sn changes from +4 in SnCl4 to +2 in SnCl2, resulting in a decrease of 2.
The product of tin and chlorine is tin(IV) chloride, represented by the chemical formula SnCl4.
SnCl4 is more covalent than SnCl2 because SnCl4 has a greater electronegativity difference between tin and chlorine atoms compared to SnCl2. This results in stronger polarity in the Sn-Cl bonds, making SnCl4 more covalent. Additionally, SnCl4 has more Cl atoms surrounding the central Sn atom, leading to a higher charge density and more covalent character in its bonds.
Tin (Sn) shows two oxidation states +2 and +4 so tin forms two types of chloride SnCl2 and SnCl4.
SnCl2 is solid because it has a higher melting point due to its crystal lattice structure, which is more stable in the solid state. SnCl4 is liquid at room temperature because it has weaker intermolecular forces between its molecules, allowing them to move more freely and thus exist in a liquid state.
When tin chloride reacts with mercury chloride, a white precipitate of mercury(I) chloride forms, while tin(IV) chloride remains in solution. The balanced chemical equation for the reaction is: SnCl2 + 2HgCl2 → SnCl4 + 2HgCl.
The molecular geometry of SnCl4 is tetrahedral. This is because tin (Sn) has 4 bonding pairs of electrons and 0 lone pairs, leading to a symmetrical tetrahedral arrangement of the chlorine atoms around the tin atom.
The oxidation number of tin can vary depending on the compound it is in. For example, in SnCl4, the oxidation number of tin is +4, while in SnCl2, the oxidation number is +2.
The compound 2 SnCl4 contains 8 chlorine atoms, as there are 4 chlorine atoms per molecule of SnCl4.