17
To find the number that, when multiplied by itself twice, equals 225, you need to find the square root of 225. The square root of 225 is 15. Therefore, the number you are looking for is 15. When you multiply 15 by itself twice (15 x 15 x 15), you get 225.
15
15 - 2x
32
2x + 7 = 15 Subtract 7 from both sides: 2x = 8 Divide both sides by 2: x = 4
The inequality representing "twice a number is at least 15" can be expressed as ( 2x \geq 15 ), where ( x ) is the unknown number. To solve for ( x ), you would divide both sides of the inequality by 2, resulting in ( x \geq 7.5 ). This means that the number must be 7.5 or greater to satisfy the condition.
2*(15 + N)
15
n = number 2(n + 15) ======
2x+15
To find the number that, when multiplied by itself twice, equals 225, you need to find the square root of 225. The square root of 225 is 15. Therefore, the number you are looking for is 15. When you multiply 15 by itself twice (15 x 15 x 15), you get 225.
The least possible number for the LCM of 15 and 105 is the same as the least possible number for all the common factors of 15 and 105 and is the LCM of 15 and 105 which just happens to be 105.
2x-15 = 53
2n + 15 = 37
15
because the closest number between these 2 numbers is 15
X = number. 4X + 9 = 2X - 15 ===========