If: 8+x = 17
Then: x = 9
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x + 8
x-8>17
Letting x be the length of the rectangle and (x - 8) be the width of the rectangle,x(x - 8) = 153,subtracting 153 from each side, x2 - 8x - 153 = 0,solving for x, (x - 17)(x + 9) = 0, then x = 17 or x = -9,substituting 17 for x, the dimensions of the rectangle are 17cm and 9cm.
8+6(x)
Let the number you are looking for be x, than 3x+8 is the algebraic expression for 8 more than triple a number.