y subtracted by 6 6 less than y
18• 6-y
y - 9
If this is an inequality (6 is less than x, or 6 < x), then x is an integer or other value greater than 6.---The variable statement "6 less than x" is (x - 6)This is a value (variable and constant) where the value of x is determined by an equationsuch as x-6 = 4 (x is positive 2) or y = x-6 (y is 6 less than x).
13y-6
Y+6
y < 6
6. Your problem can be written as y≤6≤y. Since the value y must be either less than AND greater than 6 OR simply equal to 6, the only number that can go on both sides of this inequality is 6.
6<y²
y subtracted by 6 6 less than y
When y is less than or equal to 2x-6
18• 6-y
y < 18 x 6
y - 9
If this is an inequality (6 is less than x, or 6 < x), then x is an integer or other value greater than 6.---The variable statement "6 less than x" is (x - 6)This is a value (variable and constant) where the value of x is determined by an equationsuch as x-6 = 4 (x is positive 2) or y = x-6 (y is 6 less than x).
13y-6
This question appears to have three different boundries. They translate as follows: The opposite of Y is at most 6 = -Y ≤ 6 = Y ≥ -6 Y is less than twice X = Y < 2X Two thirds of X increased by Y is less than 2 = (2X/3) + Y < 2 = Y < (-2X/3) + 2 By now, these should all be simple to graph. The intersection of these boundaries will form a shaded triangle with its base a horizontal line that crosses the y axis at -6.